Write a C program to check whether the given number is positive, negative or zero

#include(stdio.h) // place '><' in place of '(' & ')'
#include(conio.h)
int main( )
{
int no;
clrscr( );
printf("Enter the required number to check:");
scanf("%d", &no);
if(no>0)
printf("\n %d is positive number",no);
else if(no<0)
printf("\n%d is negative number",no);
else
printf("\nEntered Number is ZERO");
getch( );
return 0;
}

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Write a C program to find the greatest number between four numbers using if-else ladder

#include(stdio.h)
#include(conio.h)
int main( )
{
int a, b, c, d;
clrscr( );
printf("Enter the four different numbers:")l
scanf(" %d %d %d %d", &a, &b, &c, &d);
if(a>b && a>c && a>d)
printf("\n%d is greatest", a);
else if(b>a && b>c && b>d)
printf("\n%d is greatest", b);
else if(c>a && c>b && c>d)
printf("\n%d is greatest", c);
else
printf("\n %d is greatest", d);
getch( );
}
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Write a 'C' program to perform the selected arithmetic operation by taking two integer values using Switch Statement

#include(stdio.h)
#include(conio.h)
int main( )
{
int x,y;
char ch;
clrscr( );
printf("Enter the two integer values:);
scanf("%d%d",&x,&y);
printf("\nEnter the required arithmetic operator(+,-,*,/):");
fflush(stdin);
scanf("%c",&ch);
switch(ch)
{
case '+' : printf("\nAddition: %d", x+y); break;
case '-' : printf("\nSubstraction : %d", x-y); break;
case '*' : printf("\nMultiplication ; %d', x*y); break;
case '/': printf("\nDivision: %d", x/y); break;
default: printf("\nInvalid Arithmetic operator.");
}
getch( );
return 0;
}
Output:- Enter the two integer values: 30
20
Enter the required arithmetic operator(+,-,*,/): +
Addition: 50

Write a Program to print a Histogram showing the frequencies of different word length

"stdio.h"
"ctype.h"
"string.h" // used header files
int display(int );
void main( )
{
char st[200];
int i, count;
clrscr( );
printf("Enter the required sentence( Press Ctrl + Z to stop the sentence:");
for(i=0; (st[i]=getchar())!=EOF; i++);
printf("\n\n<---------------------Histogram fequencies--------------->");
printf("\n\n 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ..................");
for(i=0, count=0; ; i++)
{
if(st[i]==EOF)
break;
if(isspace(st[i])
count=display(count);
else
count++;
}
count= display(count);
printf("\n<----------------------------End---------------------->");
getch( );
}
int display(int ct)
{
int i;
printf("\n");
for(i=0; i<(ct*2); i++) // (ct*2) is applied becoz 1 alpha= 2 ascii syb
{
putchar(177);
}
printf("(%d)",ct);
return 0;
}

Write a C program to find the factors of a given integer.

#include(stdio.h>
#include(conio.h)
void main( )
{
int no,x;
clrscr( );
printf("Enter the required number:");
scanf("%d",&no);
printf("\nThe factors are:");
for(x=1; x<=no; x++)
{
if(no%x==0)
printf("\n%d",x);
}
getch( );
}

Output:-
Enter the required number: 27
The factors are:
1
3
9
27

Write a C program to generate the Fibonocci series using Recursion.

#include(stdio.h) // place this '<' & '>' instead of '(' & ')' before stdio.h
#include(conio.h)
int fibno(int); // function declaration.
void main( )
{
int ct, no, disp;
clrscr( );
printf("Enter the no. of terms:");
scanf("%d", &no);
printf("\n The Fibonocci series:\n");
for( ct=0; ct<=n-1; ct++) {
disp= fibno(ct); //calling function.
printf("%5d", disp);
}
getch( );
}

int fibno( int n)
{
int x, y;
if(n==0)
return 0;
else if(n==1)
return 1;
else
{
x= fibno( n-1);
y= fibno( n-2);
return (x+y);
}
}

Here the 'main' function variables
'ct' is to count the no. of values displayed in output.
'no' is for total no.of terms.
'disp' is for display the fibonocci numbers.

Here the loop 'ct<= n-1' displays the values when 'ct' equals to 'n-1'.
Suppose, Let us assume n=10 (ie., no. of terms )
Then the loop terminates, when ct==9.

Output:- Enter the no. of terms: 10

The Fibonocci series:
0 1 1 2 3 5 8 13 21 34

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Write a C program to determine the given integer is Palindrome or not.

#include(stdio.h) // place this '<' & '>' instead of '(' & ')' before stdio.h
#include(conio.h)
void main( )
{
int no, rem, rev=0, temp;
clrscr( );
printf("Enter the required integer:");
scanf("%d", &no);
temp=no;
while(temp>0)
{
rem=temp%10;
rev=(10*rev)+rem;
temp=temp/10;
}
if(no==rev)
printf("\n%d is Palindrome number", no);
else
printf("\n%d is not a palindrome string", no);
getch();
}

Output:-
Enter the required number: 141
141 is palindrome number.

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Write a C program to calculate the sum of factors of a number.

#include(stdio.h) // place this '<' & '>' instead of '(' & ')' before stdio.h
#include(conio.h)
void main( )
{
int no, sum=0, x;
clrscr( );
printf("Enter the required number :");
scanf("%d", &no);
for( x=1; x<=no; x++) {
if(no%x==0) sum=sum+x;
}
printf("\nSum of the factors of %d is: %d", no, sum);
getch( );
}

Output:-
Enter the required number: 10

Sum of the factors of 10 is: 18.
ie., 1+2+5+10 =18

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Write a C program to detect whether the given integer is Armstrong number or not.

Armstrong number:- Sum of the cubes of a individual number is known as Armstrong number.

Example:- Suppose take 153,
153= 1 + 125 + 27
ie., 153 = 1 cube + 5 cube + 3 cube
153 = 153, Then we say '153' is Armstrong number

#include(stdio.h) // place this '<' & '>' instead of '(' & ')' before stdio.h
#include(conio.h)
void main( )
{
int rem, sum=0, n, temp;
clrscr( );
printf("Enter the required number:");
scanf("%d",&n);
temp= n;
while(n>0)
{
rem=n%10;
sum = sum + (rem * rem * rem);
n=n/10;
}
if(temp == sum)
printf("\nArmstrong Number.");
else
printf("\nNot a Armstrong number.");
getch( );
}

Output:-
Enter the required number: 153
Armstrong Number.

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Write a C program to check whether the given integer is Magic number or not.

Magic number:- A number which is divisible by 9 and also after reverse if it is divisible by 9, then it is said to Magic number.

Example:- Suppose take 18
We know '18' is divisible by 9 (ie., 9 * 2 = 18)
Now After reverse '18' becomes 81.
Here '81' is also is divisible by 9 (ie., 9 * 9 =81 )
So we say '18' is a Magic number.

#include(stdio.h) // place this '<' & '>' instead of '(' & ')' before stdio.h
#include(conio.h)
void main( )
{
int rem, rev=0, n;
clrscr( );
printf("Enter the required number:");
scanf("%d",&n);
while(n>0)
{
rem=n%10;
rev=(10*rev)+ rem;
n=n/10;
}
if(rev%9== 0)
printf("\nMagic Number.");
else
printf("\nNot a Magic number.");
getch( );
}

Output:-
Enter the required number: 27
Magic Number.

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